I. OBJECTIVES:
Given a one (1) hour session, at least 85% of the students should be able to:
a.) Define position-time graph;
b.) Plot the given tabulated data using the position-time graph;
c.) Analyze and interpret graphical representation of motion;
d.) Determine and solve the slope in the graph; and
e.) Participate actively in the class discussion.
II. SUBJECT MATTER:
A. TOPIC:Position-time graph versus formulas for velocity, distance, and time of a body in motion.
B. MATERIALS : meter stick, book (Physics), visual aids on position-time graph
C. REFERNCE: Santos, Gil Nonato C. and Alfonso C. Danac.L-Physics (Investigatory Physics); Rex Bookstore Inc., Manila Philippines,2006,pp. 50-51
III. PROCEDURE:
A. REVIEW
B. TECHNIQUES/STRATEGIES:
-Inquiry approach -demonstration method
-Discussion method -problem-solving
C. LESSON PROPER:
1. Given the data for motion of a car moving eastward:
a. Draw a position-time graph or plot distance against time.
b. Compute for the average speed and velocity of the car.
c. Determine and solve for the slope.
d. Interpret the motion of the car.
D. GENERALIZATION:
Position-time graph is the graph that shows how position depends on the clock read or time. Simply distance against time. Position-time graph is very important tool in the analysis of the motion of a body, for it gives a complete picture of an object that is moving in a straight path. The data are plotted with the time as the independent variable and the position is the dependent variable. The slope represents the speed or velocity of a moving body and can be solved by locating the coordinates of points between the line graph at given time interval. In the given illustration and computed values, the car is moving in a straight path or direction towards east. The speed is constant at 15 m/s.
IV. EVALUATION:
Directions: Given the data for motion of the airplane moving eastward direction:
a. Draw a position-time graph.
b. Compute for average speed and velocity of the airplane.
c. Interpret the motion of the airplane.
| POSITION(Km) | TIME(hr.) | POSITION(Km) | TIME(hr.) |
| 0 | 0 | 60 | 4 |
| 15 | 1 | 75 | 5 |
| 30 | 2 | 90 | 6 |
| 45 | 3 | 105 | 7 |
V. ASSIGNMENT:
Directions:
Answer the following problems on a graphing paper. Show complete computations.
1. Both car A and car B leave the school when clock reads zero. Car A travels at a constant 75 km/h, while car B travels at 85 Km/h.
a. draw a position-time graph showing the motion of both cars.
b. how far are the two cars from school when the clock read 2.0h? Calculate the distances using the equation of motion and show them on your graph.
c. both cars passed gas station 100 km from the school. When did each car pass that station? Calculate the times and show them on your graph.
2. Draw a position-time graph for two cars driving to the beach, 50 km from school. Car A leaves a store 10 km from school closer to the beach at noon, and drives at 40 km/h. Car B starts from school at 12:30 pm and drives at 100 km/h. When does each get to the beach?
SEMI-DETAILED LESSON PLAN ON ACCELERATION DUE TO GRAVITY
I. OBJECTIVES:
Given a one (1) hour session, at least 85% of the students should be able to:
a. Analyze and interpret the motion of falling objects;
b. Solve problems on uniformly accelerated motion due to gravity;
c. Participate actively in the class discussion and board work/activity.
II. SUBJECT MATTER:
A. TOPIC: Acceleration due to gravity
B. MATERIALS: Book (Physics), calculator, visual aids
C. REFERENCE: Santos, Gil Nonato C. and Alfonso C Danac.L-Physics (Investigatory Physics); Rex Bookstore Inc., Manila Philippines,2006,pp.85-88
III. PROCEDURE:
A. REVIEW
B. STRATEGIES/TECHNIQUES
-Demonstration - lecture
-Discussion -problem-solving
C. LESSON PROPER
1. The teacher threw a ball upward, and he let the students observe.
2. Assuming that the initial velocity is 2,000 cm/s and was able to catch it before it reached the ground on its return.
a. What was the velocity after 1 second? after 2 seconds?
b. What was its displacement in the first second?
c. How long did it take the ball to reach its maximum height?
d. How far was this maximum height from the starting point?
e. What was its final velocity just before it reached its original position?
f. How long will it take the ball to reach a point 1,000 cm above its original position on its way down?
g. Base from the figure and computed values, how is the motion of the ball upward to its maximum height and the motion of the ball as it moves downward?
D.GENERALIZATION:
From the original position, the ball is thrown upward with certain velocity. The distance and time as the ball goes upward are increasing, the velocity is decreasing. True to the given example, the initial velocity is 2,000 cm, after 1 second the velocity is 1,020 cm/s. After 2 seconds, the velocity is decreased to 40 cm/s. Also, the distance of the ball from the original position is 1,510 cm after 1 second. After 2 seconds, the distance has become almost doubled (2,040 cm). An object thrown upward will reach a certain point or maximum height with negative value of acceleration due to gravity or simply a=g=-9.80 m/s2. When it reached the maximum it will momentarily stop and then start to move downward. At this point, v↑= 0, v↓= 0. Then the final velocity has the same magnitude as the initial velocity when the object returns to its starting point.
IV. EVALUATION:
Directions: Solve the following. Show your complete computations.
1. If you throw a ball straight up, it leaves your hand with a positive velocity of say, +20 m/s and was able to catch if before it reached the ground on its return:
a. what was its velocity after 1 second? After 2 seconds? then compare.
b. what was its displacement in the first second, in the next second?
c. how long did it take to reach its maximum height?
d. how far was this maximum height?
e. how long will it take the ball to reach a point 860 cm above your hand on its way down?
V. ASSIGNMENT:
1. Read the topic on Projectile motion.
Reference: Any Physics Book
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